- What is the monthly income of Jitu ?

I. Jitu spends 85% of his income on various expenses and remaining amount he saved.

II. Monthly saving of Jitu are rs.7500.

III. Out of total money spent by Jitu in a month, one-fifth is spent on rent and remaining amount of rs.34000 on other items.Only I and II sufficientOnly II and III sufficientOnly I and II sufficientNeither I nor II and III is sufficientAny of the two statements is sufficientOption E

Let income of Jitu = rs.x

from I and II,

15% of x = 7500

x = 7500 * 100/15 = 50000

From I and III,

x * 85/100 * 4/5 = 34000

x = 50000

from I and III

4/5 th of expenditure = 34000

expenditure = 42500

income = 42500 + 7500 = 50000

thus, answer can be find out by any of two given statement - How much time will require the train to reach from point X to point Y ?

I. The train will pass the other train of equal length of 400m running opposite in direction in 16 secs

II. Distance between point X and Y is 252 km.

III. The 400m long train crosses a signal pole in 20sec.Only I and II is sufficientOnly II and III is sufficientNeither of any statement is sufficientAll statements are sufficientOnly I and III is sufficientOption B

Statement I is not required to get answer

from statement III,

Speed of train = 400/20 = 20 m/sec

speed( in km) = 20 * 18/5 = 72 km/hr

from statement II,

time = 252/72 = 3.5 hr

statement II and III required to get answer. - What is the length of a running train A crossing another running train B ?

I. A and B two train take 18secs to cross each other, while running opposite direction.

II. The length of train B is 180mOnly I and II is sufficientOnly II is sufficientEither I or II statementNeither I nor II is sufficientOnly I sufficientOption D

Length of train A = l meters

from I, time taken by train to cross each other = 18secs

let speed of train A and B = x and y respectively

relative speed of A and B = (x + y) m/s

from II, length of train B = 180 meters

180 + l/x + y = 18

thus, we can not calculate answer by using these two statements. - What will be respective ratio of saving of A and B.

I. Income of A is 4% less than that of C and also expenditure of A is 12.5% less than that of C. B spend 3/5 th of his income.

II. C save rs. 7000 and A save rs.7400. Income of B is rs.1000 more than that of C.Only I is sufficientOnly II is sufficientEither I or II statementNeither I nor II is sufficientOnly I and II is sufficientOption E

Let income of C = 25x

income of A = 25x * 96/100 = 24x

let expenditure of A = 7y

expenditure of C = 8y

B spend 3/5 th of his his income

from II

saving of C = 7000

saving of A = 7400

Income of B is 1000 that of C

from I and II,

expenditure of A = 24x – 7y = 7400

expenditure of C = 25x – 8y = 7000

by solving two equations,

x = 600 and y = 1000

income of B = 25 * 600 + 1000 = 16000

saving B = 16000 * 2/5 = 6400

Ratio = 7400 : 6400 = 37 : 32

statement I and II is required - What is the CI on a sum at the end of 3 years ?

I. CI at the end of two years is rs.110

II. Difference between CI and SI at the end of two year is rs.100 and rate of percent is 10%.Only I is sufficientOnly II is sufficientEither I or II statementNeither I nor II is sufficientOnly I and II is sufficientOption B

From I,

Sum can not be find out as rate is not given

From II,

Difference PR^2/100^2

100 = P *100/10000

P = 10000

only statement II is sufficient. - I. x^2v- 41x + 348 = 0

II. y^2 – 20y + 99 = 0

X < YX > YX ≥ YX ≤ YX = Y or no relation.Option B

I. x^2 – 29x – 12x + 99 = 0

x = 29, 12

II. y^2 – 11y – 9y + 99 = 0

y = 11, 9 - I. 2x^2 – 2x _ 24 = 0

II. 3y^2 – 8y + 4 = 0

X < YX > YX ≥ YX ≤ YX = Y or no relation.Option E

I. 2x^2 – 8x + 6x – 24 = 0

x = 8, – 6

x = 4, -3

II. 3y^2 – 6y – 2y + 4 = 0

3y = 6, 2

y = 2, .67 - I. 5x^2 – 28x + 15 = 0

II. 3y^2 – 29 y + 68 = 0

X < YX > YX ≤ YX ≥ YX = Y or no relation.Option E

I. 5x^2 – 25x – 3x + 15 = 0

5x = 25, 3

x = 5, .6

II. 3y^2 – 17y – 12y + 68 = 0

y3y = 17, 12

y = 5.66, 4 - I. x^3 = 4913

II. y^2 = 225X < YX > YX ≤ YX ≥ YX = Y or no relation.Option B

I. x^3 = 4913

x = 17

II. y^2 = 225

y = 15, -15 - I. 2x^2 – 20x + 48 = 0

II. y^2 – 15y + 56 = 0X < YX > YX ≤ YX ≥ YX = Y or no relation.Option A

I. 2x^2 – 12x – 8x + 48 = 0

2x = 12, 8

x = 6, 4

II. y^2 – 8y – 7y + 56 = 0

y = 8, 7